[Bug c++/33403] New: "warning: missing sentinel in function call" for 0 rather than NULL

["rcrocomb at ieee dot org" <gcc-bugzilla at gcc dot gnu dot org>]

Actual version is:  gcc (GCC) 4.2.1 (Debian 4.2.1-5)

It seems unexpected that compiling the following gives a warning for the case
where '0' is passed as the sentinel rather than NULL.

#include <unistd.h>

int
with_null(void)
{
    return execlp("ls", "ls", "-l", NULL);
}

int
with_0(void)
{
    return execlp("ls", "ls", "-l", 0);
}

$ g++ -Wall -c test.cpp
test.cpp: In function 'int with_0()':
test.cpp:12: warning: missing sentinel in function call


-- 
           Summary: "warning: missing sentinel in function call" for 0
                    rather than NULL
           Product: gcc
           Version: 4.2.1
            Status: UNCONFIRMED
          Severity: trivial
          Priority: P3
         Component: c++
        AssignedTo: unassigned at gcc dot gnu dot org
        ReportedBy: rcrocomb at ieee dot org
 GCC build triplet: Same
  GCC host triplet: x86_64-linux-gnu
GCC target triplet: Same


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=33403