[Bug fortran/33285] integer too big compile error in gfortran

["kargl at gcc dot gnu dot org" <gcc-bugzilla at gcc dot gnu dot org>]

------- Comment #5 from kargl at gcc dot gnu dot org  2007-09-03 03:43 -------
(In reply to comment #4)
> (In reply to comment #2)
> > The number 2147483648 is too big.  The minus sign is a unary operator.
> > Either use the compiler option that Jerry mentioned or use 'k = - huge(k) - 1'
> > 
> option: -fno-range-check is supposed to be the default for the compiler

Huh?  No, the default for the compiler is to perform range checking.

> "In some cases, options have positive and negative forms; the negative form of
> -ffoo would be -fno-foo. This manual documents only one of these two forms,
> whichever one is not the default.'

Looks like a bug in the documentation.  I'll fix that shortly.

> It is in 4.1.X, looks like it has changed in 4.2.1

There was a bug in gfortran that allowed it to 
accepted -2147483648.  I fixed the bug with 

2006-09-07  Steven G. Kargl  <kargls@comcast.net>

        * gfortran.h (gfc_integer_info): Eliminate max_int.
        * arith.c (gfc_arith_init_1): Remove initialization of max_int.
        (gfc_arith_done_1): Remove clearing of max_int.
        (gfc_check_integer_range): Fix range chekcing of overflow.
        * simplify.c (gfc_simplify_not): Construct mask that was max_int.

You can read about the problem here:

http://gcc.gnu.org/ml/fortran/2006-09/msg00008.html


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http://gcc.gnu.org/bugzilla/show_bug.cgi?id=33285