[Bug c/32490] New: gcc does not make the difference between pointers and arrays at all

["ftwilliam at gmail dot com" <gcc-bugzilla at gcc dot gnu dot org>]

I believe this is not what gcc was supposed to do.
The code below produces a segmentation fault. I have written the reason of the
segmentation fault in a comment block toward the end of the code below.

And I don't think this is how gcc is supposed to behave.

#include <unistd.h>
#include <stdio.h>

typedef struct ch {
        char flag;
        union {
                int size;
                struct ch *next;
        } option;
} chunk;

main() {
        chunk *b;
        b=1+sbrk(4096 + 2*sizeof(chunk));

        /*
         the code below will produce a segmentation fault
         because gcc is threating b as if I was writting b[sizeof(chunk)+4096]
         but I only need to add sizeof(chunk)+4096 to the address saved in b
         and access the resulting calculated address.

         Is it really what gcc is supposed to do  ???
        */
        (*(b+sizeof(chunk)+4096)).option.next=0;
}


-- 
           Summary: gcc does not make the difference between pointers and
                    arrays at all
           Product: gcc
           Version: 4.1.2
            Status: UNCONFIRMED
          Severity: blocker
          Priority: P3
         Component: c
        AssignedTo: unassigned at gcc dot gnu dot org
        ReportedBy: ftwilliam at gmail dot com


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=32490