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[Bug c++/24939] operator< in middle of expression is parsed as template



------- Comment #4 from pinskia at gcc dot gnu dot org  2005-11-19 18:34 -------
Yep it is a dup:
template<typename T, template<typename>class al>
void slist<T, al>::merge(slist<T, al>& l) {
    node_type* cursor = before_begin().iter;
    while(cursor->next != nil && !l.empty()) {
     if (l.head->val < cursor->next->val)


*** This bug has been marked as a duplicate of 20308 ***


-- 

pinskia at gcc dot gnu dot org changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|UNCONFIRMED                 |RESOLVED
         Resolution|                            |DUPLICATE


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=24939


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