[Bug c/11751] wrong evaluation order of an expression

["d_picco at hotmail dot com" <gcc-bugzilla at gcc dot gnu dot org>]

------- Additional Comments From d_picco at hotmail dot com  2005-02-23 20:46 -------
Here is a better clarification:

Case 1
======
int a = 0;
int b = a++ + a++;
printf("b = %d\n", b);  // output is 0


Case 2
======
class A
{
  int a_;
public:
  A() : a_(0) {}

  int operator++() { return a_++; }
};

A a;
int b = a++ + a++;
printf("b = %d\n", b);  // output is 1

This is a simple case that shows how the behaviour of the operator++ should be
united.

I'm not sure what you mean by the system(...) call... I understand that the code
is undefined (meaning its up to the compiler vendor to implement as they see
fit).  I think the most fitting way is to have the above two cases unified in
behaviour... isn't one of the reasons that operators were added to C++ was to
allow user-defined types to mimic the functionality and usability of the native
C types?

-- 


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=11751