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[Bug c/16309] New: different behavior in lvalue assignment in -O0 & -O2
- From: "nakkore at libero dot it" <gcc-bugzilla at gcc dot gnu dot org>
- To: gcc-bugs at gcc dot gnu dot org
- Date: 1 Jul 2004 08:49:26 -0000
- Subject: [Bug c/16309] New: different behavior in lvalue assignment in -O0 & -O2
- Reply-to: gcc-bugzilla at gcc dot gnu dot org
Compiling with -O2 and -O0 the following code i obtain different
result with gcc version > 3.2 ( i tryed 3.3.3,3.3.4)
unsigned char dest[10],source[10]={1,2,3,4,5,6,7,8,9,10};
int main(void)
{
int i = 1;
int step = 1;
while (i < 8)
dest[i] = source[(i++*step) % 7];
for(i=0; i < 8; i++)
printf("%02x ",dest[i]);
printf("\n");
i=1;
while (i < 8)
{
dest[i] = source[(i*step) % 7];
i++;
}
for(i=0; i < 8; i++)
printf("%02x ",dest[i]);
printf("\n");
return(i+dest[6]);
}
the difference is how dest[i] is addressed via the index i.
--
Summary: different behavior in lvalue assignment in -O0 & -O2
Product: gcc
Version: 3.3.3
Status: UNCONFIRMED
Severity: normal
Priority: P2
Component: c
AssignedTo: unassigned at gcc dot gnu dot org
ReportedBy: nakkore at libero dot it
CC: gcc-bugs at gcc dot gnu dot org
GCC build triplet: Reading specs from /usr/lib/gcc-lib/i686-pc-linux-
gnu/3.3.3/spec
GCC host triplet: i386
GCC target triplet: i386
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=16309