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[Bug c++/13304] New: [regression] demangler bad output, "operator<<" insteads of "operator< <"
- From: "mec at shout dot net" <gcc-bugzilla at gcc dot gnu dot org>
- To: gcc-bugs at gcc dot gnu dot org
- Date: 4 Dec 2003 17:29:36 -0000
- Subject: [Bug c++/13304] New: [regression] demangler bad output, "operator<<" insteads of "operator< <"
- Reply-to: gcc-bugzilla at gcc dot gnu dot org
The new demangler has a problem with:
_ZStltI9file_pathSsEbRKSt4pairIT_T0_ES6_
OLD: bool std::operator< <file_path, std::basic_string<char, std::char_traits<
char>, std::allocator<char> > >(std::pair<file_path, std::basic_string<char, std
::char_traits<char>, std::allocator<char> > > const&, std::pair<file_path, std::
basic_string<char, > std::char_traits<char>, std::allocator<char> > > const&)
NEW: bool std::operator<<file_path, std::string>(std::pair<file_path, std::str
ing> const&, std::pair<file_path, std::string> const&)
This is a template for "operator<". In a nutshell, "operator< <" is needed, but
the new demangler produces "operator<<" which will tokenize badly in gdb.
OLD demangler is c++filt from binutils 2.14.
NEW demangler is from binutils HEAD 2003-11-29 16:14:33 UTC.
--
Summary: [regression] demangler bad output, "operator<<" insteads
of "operator< <"
Product: gcc
Version: 3.4
Status: UNCONFIRMED
Severity: normal
Priority: P1
Component: c++
AssignedTo: ian at wasabisystems dot com
ReportedBy: mec at shout dot net
CC: gcc-bugs at gcc dot gnu dot org
GCC build triplet: i686-pc-linux-gnu
GCC host triplet: i686-pc-linux-gnu
GCC target triplet: i686-pc-linux-gnu
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=13304