[Bug c++/13088] templatizing outer class hides specialization of inner template class

["bangerth at dealii dot org" <gcc-bugzilla at gcc dot gnu dot org>]

------- Additional Comments From bangerth at dealii dot org  2003-11-17 22:00 -------
You boost guys really have ways to write totally incomprehensible
testcases...

Anyway, the claim is justified, I guess. In essence, this boils down to
------------------
#include <iostream>

template <typename> struct S {
    template <typename> struct Type {};
};

template <typename> struct X {
    template <typename> struct Local;

};

template <typename U>
template <typename>
struct X<U>::Local {
    static void id() { std::cout << "primary\n" ;}
};

template <typename U>
template <typename T>
struct X<U>::Local<typename S<U>::template Type<T> > {
    static void id() { std::cout << "specialized\n" ;}
};


int main() {
  X<int>::Local<S<int>::Type<int> >::id();
}
-------------------------------

For this, we get

g/x> /home/bangerth/bin/gcc-3.3.2/bin/c++ x.cc ; ./a.out
primary

The same holds for every other gcc version that doesn't ICE outright. On
the other hand, icc for example prints "specialized". I guess it's wrong
that we don't match the partial specialization of X::Local.

W.

-- 
           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|WAITING                     |NEW
     Ever Confirmed|                            |1
   Last reconfirmed|0000-00-00 00:00:00         |2003-11-17 22:00:47
               date|                            |


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=13088