[Bug c/12203] New: nearbyint returns always 895

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http://gcc.gnu.org/bugzilla/show_bug.cgi?id=12203

           Summary: nearbyint returns always 895
           Product: gcc
           Version: 3.0.3
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: c
        AssignedTo: unassigned at gcc dot gnu dot org
        ReportedBy: sk at mathematik dot uni-ulm dot de
                CC: gcc-bugs at gcc dot gnu dot org
 GCC build triplet: i686-pc-linux-gnu
  GCC host triplet: i686-pc-linux-gnu
GCC target triplet: i686-pc-linux-gnu

	Calling nearbyint returns always 895.0

Environment:
System: Linux johann 2.4.21 #2 Sun Aug 17 20:52:39 CEST 2003 i686 unknown
Architecture: i686

	
host: i686-pc-linux-gnu
build: i686-pc-linux-gnu
target: i686-pc-linux-gnu
configured with: ./configure --enable-languages=c++

How-To-Repeat:
	Compile and run:

#include <math.h>
#include <stdio.h>

void show (double x)
{
   printf("nearbyint(%+.3e) = %d\n", x, (int)(nearbyint(x)));
   if(0.0 == x) return;
   x = -x;
   printf("nearbyint(%+.3e) = %d\n", x, (int)(nearbyint(x)));
   x = 1/x;
   printf("nearbyint(%+.3e) = %d\n", x, (int)(nearbyint(x)));
   x = -x;
   printf("nearbyint(%+.3e) = %d\n", x, (int)(nearbyint(x)));
}

int main ()
{
   show(1.1);
   show(11);
   show(111.1);
}