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Re: libstdc++/9747: allocator<T>::deallocate(*, int ) does not call ::operator delete(size_t).
- From: paolo at gcc dot gnu dot org
- To: axiong at ca dot ibm dot com, gcc-bugs at gcc dot gnu dot org, gcc-prs at gcc dot gnu dot org, nobody at gcc dot gnu dot org, paolo at gcc dot gnu dot org
- Date: 18 Feb 2003 20:21:16 -0000
- Subject: Re: libstdc++/9747: allocator<T>::deallocate(*, int ) does not call ::operator delete(size_t).
- Reply-to: paolo at gcc dot gnu dot org, axiong at ca dot ibm dot com, gcc-bugs at gcc dot gnu dot org, gcc-prs at gcc dot gnu dot org, nobody at gcc dot gnu dot org, paolo at gcc dot gnu dot org, gcc-gnats at gcc dot gnu dot org
Synopsis: allocator<T>::deallocate(*, int ) does not call ::operator delete(size_t).
Responsible-Changed-From-To: unassigned->paolo
Responsible-Changed-By: paolo
Responsible-Changed-When: Tue Feb 18 20:21:16 2003
Responsible-Changed-Why:
Triaged.
State-Changed-From-To: open->closed
State-Changed-By: paolo
State-Changed-When: Tue Feb 18 20:21:16 2003
State-Changed-Why:
This is well known and intended for performance sake.
Look at include/bits/stl_alloc.h in your src distribution:
a new/delete allocator is available via __new_alloc and, if
you like, you can choose it at build time by simply changing
the __alloc typedef.
Thanks, Paolo.
http://gcc.gnu.org/cgi-bin/gnatsweb.pl?cmd=view%20audit-trail&database=gcc&pr=9747