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Re: c++/9666: Arg conversion problem with operator new
- From: bangerth at dealii dot org
- To: BrainChild at Skyler dot com, gcc-bugs at gcc dot gnu dot org, gcc-prs at gcc dot gnu dot org, nobody at gcc dot gnu dot org
- Date: 14 Feb 2003 21:22:28 -0000
- Subject: Re: c++/9666: Arg conversion problem with operator new
- Reply-to: bangerth at dealii dot org, BrainChild at Skyler dot com, gcc-bugs at gcc dot gnu dot org, gcc-prs at gcc dot gnu dot org, nobody at gcc dot gnu dot org, gcc-gnats at gcc dot gnu dot org
Synopsis: Arg conversion problem with operator new
State-Changed-From-To: open->analyzed
State-Changed-By: bangerth
State-Changed-When: Fri Feb 14 21:22:28 2003
State-Changed-Why:
Confirmed -- well, sort of, since I am not sure whether this
is legal. Here's the code slightly reformatted:
-------------------------
#include <cstddef>
struct X {
operator size_t ();
operator size_t () const;
};
char *f2 (const X &x) { return new char[x]; }
--------------------------
The compiler complains:
tmp/g> /home/bangerth/bin/gcc-3.4-pre/bin/c++ -c x.cc
x.cc: In function `char* f2(const X&)':
x.cc:8: error: expression in new-declarator must have integral or enumeration
type
Now, I tend to think that the code is illegal, due to 5.3.4.7:
7 Every constant-expression in a direct-new-declarator shall be an inte-
gral constant expression (_expr.const_) and evaluate to a strictly
positive value. The expression in a direct-new-declarator shall have
integral type (_basic.fundamental_) with a non-negative value.
Then, on the other hand, this code compiles:
-----------------------
#include <cstddef>
struct X {
/* operator size_t (); */
operator size_t () const;
};
char *f2 (const X &x) { return new char[x]; }
-----------------------
I should think that the presence of the second non-const
operator shouldn't make a difference since x is a constant
reference...
Can someone clarify?
W.
http://gcc.gnu.org/cgi-bin/gnatsweb.pl?cmd=view%20audit-trail&database=gcc&pr=9666