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Re: c++/9460: parse error on template member function
- From: "Giovanni Bajo" <giovannibajo at libero dot it>
- To: "Wolfgang Bangerth" <bangerth at ticam dot utexas dot edu>,"Oliver Schoenborn" <oliver dot schoenborn at utoronto dot ca>
- Cc: <gcc-gnats at gcc dot gnu dot org>,<gcc-bugs at gcc dot gnu dot org>
- Date: Wed, 29 Jan 2003 10:09:39 +0100
- Subject: Re: c++/9460: parse error on template member function
- References: <Pine.LNX.4.44.0301281508490.8332-100000@gandalf.ticam.utexas.edu>
----- Original Message -----
From: "Wolfgang Bangerth" <bangerth@ticam.utexas.edu>
To: "Oliver Schoenborn" <oliver.schoenborn@utoronto.ca>
Cc: <gcc-gnats@gcc.gnu.org>
Sent: Tuesday, January 28, 2003 10:14 PM
Subject: Re: c++/9460: parse error on template member function
> It would be different if you would call
> Foo().F1<A> ();
> in which case you would have to use
> Foo().template F1<A> ();
Sorry for the confusion. The problem is, the compiler still has symmetric
behaviour:
Foo().F1<A>() compiles with no errors, while it needs the template keyword.
(accept-illegal)
In my first code snippet, if you remove Bar::F1, the code fails to compile.
(reject-legal).
Giovanni Bajo