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preprocessor/1976: different treatment of shift in preprocessor and compiler
- To: gcc-gnats at gcc dot gnu dot org
- Subject: preprocessor/1976: different treatment of shift in preprocessor and compiler
- From: fl at abas dot de
- Date: 14 Feb 2001 10:07:36 -0000
- Reply-To: fl at abas dot de
>Number: 1976
>Category: preprocessor
>Synopsis: different treatment of shift in preprocessor and compiler
>Confidential: no
>Severity: serious
>Priority: medium
>Responsible: unassigned
>State: open
>Class: sw-bug
>Submitter-Id: net
>Arrival-Date: Wed Feb 14 02:16:01 PST 2001
>Closed-Date:
>Last-Modified:
>Originator: gcc
>Release: gcc version 2.95.2 19991024 (release)
>Organization:
>Environment:
gcc -v:Reading specs from /usr/local/lib/gcc-lib/i686-pc-linux-gnu/2.95.2/specs
gcc version 2.95.2 19991024 (release)
uname -a: Linux fozzie 2.2.16-3 #1 Mit Jan 17 14:09:36 CET 2001 i686 unknown
>Description:
Hi,
the following programm can be compiled and produces the output
hallo
#include <stdio.h>
int main(int argc, char **argv)
{
#if 4 << 31 == 0
blablabla
#endif
if ((4 << 31) == 0){
printf("hallo\n");
}
}
This means that the precprocessor evaluates 4 << 31 == 0 to false,
however, at runtime the expression ist true.
>How-To-Repeat:
compile the mentioned program (without any options) and run it.
>Fix:
>Release-Note:
>Audit-Trail:
>Unformatted: