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1 void abort (void);
2
3 void parloop (int N)
4 {
5 int i;
6 int x[10000000];
7
8 for (i = 0; i < N; i++)
9 x[i] = i + 3;
10
11 for (i = 0; i < N; i++)
12 {
13 if (x[i] != i + 3)
14 abort ();
15 }
16 }
17
18 int main(void)
19 {
20 parloop(10000000);
21
22 return 0;
23 }
24
25 /* Check that parallel code generation part make the right answer. */
26 /* { dg-final { scan-tree-dump-times "1 loops carried no dependency" 2 "graphite" } } */
27 /* { dg-final { cleanup-tree-dump "graphite" } } */
28 /* { dg-final { scan-tree-dump-times "loopfn" 5 "optimized" } } */
29 /* { dg-final { cleanup-tree-dump "parloops" } } */
30 /* { dg-final { cleanup-tree-dump "optimized" } } */
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