using T = int;
consteval bool f()
{
  T t = 42;
  t.~T();
  return (t == 42);
}

bool x = f();

This code should not compile, as `f` invokes undefined behavior during constant evaluation, as Clang diagnoses:

<source>:9:10: error: call to consteval function 'f' is not a constant expression
bool x = f();
         ^
<source>:6:11: note: read of object outside its lifetime is not allowed in a constant expression
  return (t == 42);
          ^

The specific usage with `int` here was not UB until C++20 (although pseudo-destructors weren't allowed in constant expressions until C++20 anyway), but as of http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2020/p0593r6.html#pseudo-destructor-calls pseudo-destructors end the lifetime of the operand.