| Summary: | Showing incompatible type when types are same. | ||
|---|---|---|---|
| Product: | gcc | Reporter: | Srinivas Nayak <sinu.nayak2001> |
| Component: | c | Assignee: | Not yet assigned to anyone <unassigned> |
| Status: | RESOLVED INVALID | ||
| Severity: | normal | ||
| Priority: | P3 | ||
| Version: | 4.6.2 | ||
| Target Milestone: | --- | ||
| Host: | Target: | ||
| Build: | Known to work: | ||
| Known to fail: | Last reconfirmed: | ||
Arrays decay to pointers when they are rlvalues. C has no array assignment. |
#include <stdio.h> int main() { int k[3][3] = {{1,2,3},{4,5,6},{7,8,9}}; int (*c)[3]; int (*d)[3]; c = k+1; d = k+2; *c = *d; //error: incompatible types when assigning to type 'int[3]' from type 'int *' k[0] = k[1]; //error: incompatible types when assigning to type 'int[3]' from type 'int *' printf("%d\n", (*c)[0]); printf("%d\n", (*d)[0]); return 0; } In the above code, errors are shown as commented. No doubt, it is a tricky attempt to assign an array to another array. However, aren't the types of both left hand side and right hand side same? Sincerely, Srinivas Nayak