| Summary: | type qualifiers ignored on function return type | ||
|---|---|---|---|
| Product: | gcc | Reporter: | littlestar <cnstar9988> |
| Component: | c | Assignee: | Not yet assigned to anyone <unassigned> |
| Status: | RESOLVED INVALID | ||
| Severity: | normal | CC: | gcc-bugs |
| Priority: | P3 | ||
| Version: | 4.2.4 | ||
| Target Milestone: | --- | ||
| Host: | Target: | ||
| Build: | Known to work: | 3.4.6 | |
| Known to fail: | 4.2.2 4.2.3 4.2.4 | Last reconfirmed: | |
The const in "const THANDLE" applies to the pointer type and not the element the pointer is pointing to. So the warning is correct. but how to applies to the pointer type and the element
the pointer is pointing to.
I don't want someone modify my pointer and the pointing to?
but the following code has no warning, why?
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
typedef struct testabc {int Class;}THANDLE;
const THANDLE* test()
{
THANDLE *x;
x = (THANDLE*)2;
return x;
}
int main(int argc, char **argv)
{
const THANDLE *p= test();
return (int)p;
}
"const THANDLE" in the first case is equivalant to "THANDLE* const" when THANDLE a struct.
> but how to applies to the pointer type and the element
> the pointer is pointing to.
With the typedefs, you can't.
|
the following code generate a warning on gcc 4.2.4 warning: type qualifiers ignored on function return type #include <stdio.h> #include <string.h> #include <stdlib.h> typedef struct testabc{int class;}* THANDLE; const THANDLE test() { THANDLE x; x = (THANDLE)2; return x; } int main(int argc, char **argv) { const THANDLE p = test(); return (int)p; }