| Summary: | Beats me | ||
|---|---|---|---|
| Product: | gcc | Reporter: | Ivan Godard <igodard> |
| Component: | c++ | Assignee: | Not yet assigned to anyone <unassigned> |
| Status: | RESOLVED DUPLICATE | ||
| Severity: | normal | CC: | gashlerm, gcc-bugs, igodard, metcalf, vhaisman |
| Priority: | P2 | ||
| Version: | 3.4.0 | ||
| Target Milestone: | --- | ||
| Host: | Target: | ||
| Build: | Known to work: | ||
| Known to fail: | Last reconfirmed: | ||
Read http://gcc.gnu.org/gcc-3.4/changes.html In a template definition, unqualified names will no longer find members of a dependent base (as specified by [temp.dep]/3 in the C++ standard). For example, template <typename T> struct B { int m; int n; int f (); int g (); }; int n; int g (); template <typename T> struct C : B<T> { void h () { m = 0; // error f (); // error n = 0; // ::n is modified g (); // ::g is called } }; You must make the names dependent, e.g. by prefixing them with this->. Here is the corrected definition of C<T>::h, template <typename T> void C<T>::h () { this->m = 0; this->f (); this->n = 0 this->g (); } As an alternative solution (unfortunately not backwards compatible with GCC 3.3), you may use using declarations instead of this->: template <typename T> struct C : B<T> { using B<T>::m; using B<T>::f; using B<T>::n; using B<T>::g; void h () { m = 0; f (); n = 0; g (); } }; Oh yeah - I've fallen into (and reported) that one before. How quickly we forget! You know, a "perhaps you meant 'this->foo'?" in the diagnostic ould cut down on the redundant reports you guys get :-) Ivan Reopening to ... |
enum endianness {littleEndian, hostEndianness, bigEndian}; template<typename T> class sBigEndian { public: T payload; }; template<typename T> class asBigEndian : public sBigEndian<T> { public: operator T() { return payload; } }; gets you: ~/ootbc/members/src$ g++ foo.cc foo.cc: In member function `asBigEndian<T>::operator T()': foo.cc:13: error: `payload' undeclared (first use this function) foo.cc:13: error: (Each undeclared identifier is reported only once for each function it appears in.)