| Summary: | [3.4 regression] Spurious warning for comma-operator in templates | ||
|---|---|---|---|
| Product: | gcc | Reporter: | Wolfgang Bangerth <bangerth> |
| Component: | c++ | Assignee: | Not yet assigned to anyone <unassigned> |
| Status: | RESOLVED DUPLICATE | ||
| Severity: | critical | CC: | gcc-bugs |
| Priority: | P1 | ||
| Version: | 3.4.0 | ||
| Target Milestone: | 3.4.0 | ||
| Host: | Target: | ||
| Build: | Known to work: | ||
| Known to fail: | Last reconfirmed: | ||
Subject: Re: [3.4 regression] Spurious warning for comma-operator in templates > *** This bug has been marked as a duplicate of 11512 *** Darn, I knew I had seen this somewhere before. Thanks Andrew! W. ------------------------------------------------------------------------- Wolfgang Bangerth email: bangerth@ices.utexas.edu www: http://www.ices.utexas.edu/~bangerth/ |
Here's a very annoying regression that swamps my builds in warning messages: ------------------------------ void g (int, int); template <int> void f () { for (int i;; ++i, ++i) g(i,i); } template void f<1> (); ------------------------------ g/x> /home/bangerth/bin/gcc-3.4-pre/bin/c++ -W -Wall -c x.cc x.cc: In function `void f()': x.cc:4: warning: left-hand operand of comma expression has no effect Clearly, the left hand side of the comma expression _does_ have an effect. The warning disappears when the function is not a template. W.