Function-like macros can take arguments, just like true functions. To define a macro that uses arguments, you insert parameters between the pair of parentheses in the macro definition that make the macro function-like. The parameters must be valid C identifiers, separated by commas and optionally whitespace.
To invoke a macro that takes arguments, you write the name of the macro followed by a list of actual arguments in parentheses, separated by commas. The invocation of the macro need not be restricted to a single logical line--it can cross as many lines in the source file as you wish. The number of arguments you give must match the number of parameters in the macro definition. When the macro is expanded, each use of a parameter in its body is replaced by the tokens of the corresponding argument. (You need not use all of the parameters in the macro body.)
As an example, here is a macro that computes the minimum of two numeric values, as it is defined in many C programs, and some uses.
#define min(X, Y) ((X) < (Y) ? (X) : (Y)) x = min(a, b); ==> x = ((a) < (b) ? (a) : (b)); y = min(1, 2); ==> y = ((1) < (2) ? (1) : (2)); z = min(a + 28, *p); ==> z = ((a + 28) < (*p) ? (a + 28) : (*p));
(In this small example you can already see several of the dangers of macro arguments. See Macro Pitfalls, for detailed explanations.)
Leading and trailing whitespace in each argument is dropped, and all whitespace between the tokens of an argument is reduced to a single space. Parentheses within each argument must balance; a comma within such parentheses does not end the argument. However, there is no requirement for square brackets or braces to balance, and they do not prevent a comma from separating arguments. Thus,
macro (array[x = y, x + 1])
passes two arguments to
array[x = y and
1]. If you want to supply
array[x = y, x + 1] as an argument,
you can write it as
array[(x = y, x + 1)], which is equivalent C
All arguments to a macro are completely macro-expanded before they are substituted into the macro body. After substitution, the complete text is scanned again for macros to expand, including the arguments. This rule may seem strange, but it is carefully designed so you need not worry about whether any function call is actually a macro invocation. You can run into trouble if you try to be too clever, though. See Argument Prescan, for detailed discussion.
min (min (a, b), c) is first expanded to
min (((a) < (b) ? (a) : (b)), (c))
and then to
((((a) < (b) ? (a) : (b))) < (c) ? (((a) < (b) ? (a) : (b))) : (c))
(Line breaks shown here for clarity would not actually be generated.)
You can leave macro arguments empty; this is not an error to the
preprocessor (but many macros will then expand to invalid code).
You cannot leave out arguments entirely; if a macro takes two arguments,
there must be exactly one comma at the top level of its argument list.
Here are some silly examples using
min(, b) ==> (( ) < (b) ? ( ) : (b)) min(a, ) ==> ((a ) < ( ) ? (a ) : ( )) min(,) ==> (( ) < ( ) ? ( ) : ( )) min((,),) ==> (((,)) < ( ) ? ((,)) : ( )) min() error--> macro "min" requires 2 arguments, but only 1 given min(,,) error--> macro "min" passed 3 arguments, but takes just 2
Whitespace is not a preprocessing token, so if a macro
foo () and
foo ( ) both supply it an
empty argument. Previous GNU preprocessor implementations and
documentation were incorrect on this point, insisting that a
function-like macro that takes a single argument be passed a space if an
empty argument was required.
Macro parameters appearing inside string literals are not replaced by their corresponding actual arguments.
#define foo(x) x, "x" foo(bar) ==> bar, "x"