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Re: -fvisibility=hidden vs. extern "C"

From: Jason Merrill <jason at redhat dot com>
To: Jakub Jelinek <jakub at redhat dot com>
Cc: Benjamin Kosnik <bkoz at redhat dot com>, libstdc++ at gcc dot gnu dot org
Date: Fri, 21 Jul 2006 12:53:08 -0400
Subject: Re: -fvisibility=hidden vs. extern "C"
References: <20060721010103.21c79138.bkoz@redhat.com> <20060721064253.GA32572@devserv.devel.redhat.com>

Jakub Jelinek wrote:

In the eh_personality.ii you posted with -fvisibility the prototype
of __gxx_personality_v0 is marked with default visibility (as it is
surrounded by #pragma GCC visibility {push(default), pop} pair),
but the actual definition is not marked in any way.  As it is a definition,
-fvisibility=hidden causes its visibility to be specified to hidden,
and as hidden is stronger visibility than default, hidden wins.

Hmm, this shouldn't happen; if the prototype has explicit visibility it should override -fvisibility.

Jason

Follow-Ups:
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References:
- -fvisibility=hidden vs. extern "C"
  - From: Benjamin Kosnik
- Re: -fvisibility=hidden vs. extern "C"
  - From: Jakub Jelinek

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