Re: [RFC] sscanf vs ERANGE vs finitel

[Paolo Carlini <pcarlini at suse dot de>]

Paolo Carlini wrote:

> Andreas Schwab wrote:
>
> > Yes, Inf and NaN are both in range, but not finite.
>
> Ah, ok, now I see. You mean when INF, INFINITY and so on are parsed,
> sscanf does *not* set errno, indeed. I forgot that, my bad.

But now, I'm asking, *if* sscanf is not given in input the special strings
"inf", "infinity", and so on (this can never happen for the uses in the c++
runtime library, forgot to tell you!), in all the other cases, the 
returned value
can only be inf when simultaneously ERANGE is set, right???

If this is true major simplifications are possible in those functions... ;)

Paolo.