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[OT] Re: Controlling the garbage collector (GC) at RT?


Hi Hans,

You also need to touch the resulting memory.  Try something like
char *v = sbrk( 1000000 );
for (char *p = v; p < p + 1000000; ++p) *p = 42;
in the loop.
I'll try something similar tomorrow, thanks alot - although I will need modify the ever true statement "p < p + 1M" to "p < v + 1M"...
So, now I tried this:

#include <unistd.h>

int main( int i )
{
  while ( 1 ) {
    char *v = sbrk( 1000000 );
    char *p;
    for (*p = v; p < v + 1000000; ++p) {
      *p = 42;
    } // for

    printf( "%x\n\n", v );
  } // while
} // main

And still nothing happens with the memory consumption, although the pointer ends up at 0xffffffff...
Nooow, after modifying the program to

for ( p = v; ...

it "works" - the application is terminated by the kernel.
This goes regardless what [0,1,2] is echo'ed into "/proc/sys/vm/overcommit_memory"...
The kernel reports:


Out of Memory: Killed process 36 (sbrktest)

But what should the outcome really had been?

I tried the same on an elder kernel on a different target - 2.4.17 and i386 - and the same outcome...

BR,
 Martin Egholm

-----Original Message-----
From: java-owner@gcc.gnu.org [mailto:java-owner@gcc.gnu.org] On Behalf Of Martin Egholm Nielsen
Sent: Wednesday, February 23, 2005 12:04 AM
To: java@gcc.gnu.org
Subject: Re: Controlling the garbage collector (GC) at RT?




It seems to me that the only problem here is that this
still seems to
happen with overcommit-accounting set to 2.
I would expect that you can reproduce this problem with a
program that
alternately allocates a few MB with sbrk, and then touches the allocated memory. If you can't, there's something really
weird going
on here. If you can, it'll give you a test case for the kernel people.
I tried the following:

#include <unistd.h>

int main( int i )
{
  while ( 1 ) {
    void *v = sbrk( 100000 );
    // sleep( 1 );
  } // while
} // main

But that doesn't result in anything - the memory usage for the application does not grow...
Are there anything else I should do to allocate the memory?


BR,
 Martin


Hans

On Wed, 16 Feb 2005, Martin Egholm Nielsen wrote:



Hi Hans,



It would indeed be interesting to know why the Linux kernel



kills the application rather than returning failure.



Sure, but how to do that? Any guidelines?



What do you see on the console? Anything in the system log? Does strace tell you anything?



Below is the last part of "strace -f -F -i -v". It doesn't



really look


like there's anything of value?

// Martin

[pid 75] [0f833558] write(1, "*** MEM CHUNK TAKEN:



8388608\n", 29***


MEM CHUNK TAKEN: 8388608
) = 29
[pid 75] [0f839834] brk(0x12d15000) = 0x12d15000
[pid 75] [0f839834] brk(0x12d25000) = 0x12d25000
[pid 75] [0f81126c] getpid() = 75
[pid 75] [0f799444] kill(77, SIGPWR <unfinished ...>
[pid 76] [0f840e2c] <... poll resumed> [{fd=3, events=POLLIN,
revents=POLLIN}
], 1, 2000) = 1
[pid 75] [0f799444] <... kill resumed> ) = 0
[pid 76] [0f81127c] getppid() = 75
[pid 76] [0f833548] read(3,
"\20\7/\234\0\0\0\4\17\374$0\20\7/\240$\0\0B\17\3
72j(\177"..., 148) = 148
[pid 76] [0f840e2c] poll( <unfinished ...>
[pid 75] [0f799444] kill(77, SIGXCPU) = 0
[pid 75] [0f839834] brk(0x13525000) = 0x13525000
[pid 75] [0f833558] write(1, "*** MEM CHUNK TAKEN:



8388608\n", 29***


MEM CHUNK TAKEN: 8388608
) = 29
[pid 75] [0f839834] brk(0x13535000) = 0x13535000
[pid 75] [0f839834] brk(0x13545000) = 0x13545000
[pid 75] [0f839834] brk(0x13d45000) = 0x13d45000
[pid 75] [0f833558] write(1, "*** MEM CHUNK TAKEN:



8388608\n", 29***


MEM CHUNK TAKEN: 8388608
) = 29
[pid 76] [0f840e2c] <... poll resumed> [{fd=3,



events=POLLIN}], 1,


2000) = 0
[pid    76] [0f840e2c] --- SIGTERM (Terminated) ---
#












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