Simple test:
---
struct U {
unsigned s: 1;
};
struct V {
unsigned short o: 7;
unsigned short u: 1;
};
extern struct U t[];
extern struct V d[];
unsigned
foo ()
{
struct V descr = d[0];
unsigned osize = descr.o;
if ( descr.u )
{
struct U udata = t[osize];
if (udata.s) osize++;
}
return osize;
}
---
Compiled with specified gcc:
gcc -v
Using built-in specs.
COLLECT_GCC=/tools/local/gcc-5.2.0/bin/gcc
COLLECT_LTO_WRAPPER=/tools/local/gcc-5.2.0/libexec/gcc/x86_64-unknown-linux-gnu/5.2.0/lto-wrapper
Target: x86_64-unknown-linux-gnu
Configured with: ../gcc-5.2.0/configure
--prefix=/tools/local/gcc-5.2.0 --program-suffix=-5.2.0
--with-as=/tools/local/binutils-2.24/bin/as
--with-ld=/tools/local/binutils-2.24/bin/ld
Thread model: posix
gcc version 5.2.0 (GCC)
---
with options: -02 -S
---
Yields assembler:
---
foo:
movzbl d(%rip), %eax
andl $127, %eax
cmpb $0, d(%rip)
movzbl %al, %eax // <----- why this is here?
jns .L2
movl %eax, %edx
movl t(,%rdx,4), %edx
andl $1, %edx
cmpb $1, %dl
sbbl $-1, %eax
.L2:
rep ret
---
I can not understand why second movzbl is here? andl already bitwise
and register eax with 127, why do someone need to zero-extend it one
more time?
May be some optimization missed here and it makes sense to file a
ticket in bugzilla? Or maybe I do not understand something?
Problem go away if I change unsigned short to unsigned int in bitfield
type inside structure V.