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Re: extending fpmuls

From: Jakub Jelinek <jakub at redhat dot com>
To: Frederic Riss <frederic dot riss at gmail dot com>
Cc: David Miller <davem at davemloft dot net>, gcc at gcc dot gnu dot org, rth at redhat dot com
Date: Tue, 25 Oct 2011 11:24:23 +0200
Subject: Re: extending fpmuls
References: <20111024.231229.1740330731072102105.davem@davemloft.net> <20111025080050.GZ27949@sunsite.ms.mff.cuni.cz> <CAKk_3s-_ss5C9BGeJwyGJTJrYTu14wnmmdNkRuuKYYrCkdv1jg@mail.gmail.com>
Reply-to: Jakub Jelinek <jakub at redhat dot com>

On Tue, Oct 25, 2011 at 11:12:25AM +0200, Frederic Riss wrote:
> Could you explain why the overflow is required here with respect to
> the standard?

Because most of gcc targets (the only exception is i386 and m68k I think)
define FLT_EVAL_METHOD 0, so say that floating point expressions are
evaluated to the range and precision of corresponding type.
And that is quite desirable behavior for many applications.

	Jakub

References:
- extending fpmuls
  - From: David Miller
- Re: extending fpmuls
  - From: Jakub Jelinek
- Re: extending fpmuls
  - From: Frederic Riss

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