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Re: gengtype needs for C++?
On Wed, Jun 30, 2010 at 11:51:46AM +0200, Paolo Bonzini wrote:
>
> Now:
>
> /* A zillion macros like this one: */
[...]
>
>
> After:
>
> /* Two templates like these: */
> template <class T> static inline void
> ggc_mark_all (T *const x)
> {
> if (x != NULL) ggc_mark_all_1 (x);
> }
>
> template <class T> static inline void
> ggc_mark_all_1 (T *const x)
> {
> gcc_unreachable();
> }
>
> /* Many specializations like this (generated by gengtype). */
> template <> void
> ggc_mark_all_1 (struct eh_catch_d * const x)
> {
> if (ggc_test_and_set_mark (x))
> {
> ggc_mark_all ((*x).next_catch);
> ggc_mark_all ((*x).prev_catch);
> ggc_mark_all ((*x).type_list);
> ggc_mark_all ((*x).filter_list);
> ggc_mark_all ((*x).label);
> }
> }
>
> /* A single specialization for all std::vectors, whose treatment
> is simpler than VECs in gengtype: */
> template <std::vector<T, ggc_allocator> > void
> ggc_mark_all_1 (std::vector<T, ggc_allocator> * const x)
> {
> typedef typename std::vector<T, ggc_allocator> vec_type;
> typedef typename vec_type::iterator iterator;
>
> for (iterator p = x.begin(), q = x.end(); p != q; ++p)
> gcc_mark_all (*p);
> }
>
>
> Of course it may be too bad for compilation times, it may require
> other changes (e.g. to the way roots are enumerated, or because
> templates require stuff to be in header files that used to be in
> gtype-desc.c), it may not work at all. No idea. :)
Thanks for the nice explanations.
Cheers.
--
Basile STARYNKEVITCH http://starynkevitch.net/Basile/
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