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Re: std::isfinite broken?

From: Paolo Carlini <paolo dot carlini at oracle dot com>
To: Neal Becker <ndbecker2 at gmail dot com>
Cc: gcc at gcc dot gnu dot org
Date: Mon, 28 Jul 2008 13:56:17 +0200
Subject: Re: std::isfinite broken?
References: <g6ka48$btf$1@ger.gmane.org> <488DB11B.7010304@oracle.com> <g6kbrp$ham$1@ger.gmane.org>

Neal Becker wrote:

I found that compiling without -ffast-math would allow std::isfinite to
work.  Sorry if the statement was confusing.  The code looks something
like:
[calculate x] if (not isfinite (x)) throw std::runtime_error ("blah")

Well, -ffast-math implies -ffinite-math-only, I think you have to pass -fno-finite-math-only if you want to deal correctly with infinities.

Paolo.

References:
- std::isfinite broken?
  - From: Neal Becker
- Re: std::isfinite broken?
  - From: Paolo Carlini
- Re: std::isfinite broken?
  - From: Neal Becker

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