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Re: -Wextra and enumerator/non-enumerator in conditional expressions

From: Jim Wilson <wilson at specifix dot com>
To: "Ching, Jimen \(US SSA\)" <jimen dot ching at baesystems dot com>
Cc: gcc at gcc dot gnu dot org
Date: Mon, 09 Apr 2007 12:25:14 -0700
Subject: Re: -Wextra and enumerator/non-enumerator in conditional expressions
References: <5712874E51C67B4E8BE9408DED619D7A439616@blums0015.bluelnk.net>

Ching, Jimen (US SSA) wrote:

According to the manual, I should be getting a warning, but I don't.
Did
I misunderstand the manual?

A conditional expression, as per the ISO C/C++ standards, is an expression of the form (A ? B : C). There is no conditional expression in your testcase.

Also, in order to see the warning, you have to use a type that the enum does not easily convert to. Something like return (1 ? BAR : 1L); works. -- Jim Wilson, GNU Tools Support, http://www.specifix.com

References:
- -Wextra and enumerator/non-enumerator in conditional expressions
  - From: Ching, Jimen \(US SSA\)

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