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Re: Getting a tree node for a field of a variable

From: Mike Stump <mrs at apple dot com>
To: Ferad Zyulkyarov <feradz at gmail dot com>
Cc: gcc at gcc dot gnu dot org
Date: Fri, 19 Jan 2007 09:56:45 -0800
Subject: Re: Getting a tree node for a field of a variable
References: <f7b109350701180748i2d022e2dy9607645cb8996be8@mail.gmail.com> <m3vej49td9.fsf@dhcp-172-18-118-195.corp.google.com> <f7b109350701190342y7f13e975pf97f4f0c1197e845@mail.gmail.com>

On Jan 19, 2007, at 3:42 AM, Ferad Zyulkyarov wrote:

Is it possible to write a short example how a it could be referred the
tree of variable field?

Sure, just compile up the C code for what you want to do, run the debugger, watch what it builds and how it builds it. If you want to know what it looks like in the end, just print the built tree. However, if you have a complex language like C++, accessing a field can be, well, kinda different. You cannot employ the same techniques that you learn from C to C++.

References:
- Getting a tree node for a field of a variable
  - From: Ferad Zyulkyarov
- Re: Getting a tree node for a field of a variable
  - From: Ian Lance Taylor
- Re: Getting a tree node for a field of a variable
  - From: Ferad Zyulkyarov

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