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Re: [OT] __builtin_cpow((0,0),(0,0))
Duncan Sands wrote:
aren't __builtin_cpow and friends language independent? I mean, if a
front-end sees a x^y then presumably it ends up being turned into a
call to a __builtin_?pow by the back-end. If so, then conforming to
the C99 and C++ standards isn't enough: the standards for all gcc
supported languages need to be checked.
This is a good question, indeed. I don't think Ada, for instance, is using
__builtin_cpow internally, or cpow, for that matter, since many widespread
libc implementations have cpow(0,0) returning (nan, nan) contra the Ada
RM, as mentioned by Robert Dewar.
Paolo.
- References:
- __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))
- Re:[OT] __builtin_cpow((0,0),(0,0))
- Re: [OT] __builtin_cpow((0,0),(0,0))
- Re: [OT] __builtin_cpow((0,0),(0,0))