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Re: (printf) ("hello world\n");

From: Robert Dewar <dewar at gnat dot com>
To: Andreas Schwab <schwab at suse dot de>
Cc: Eyal Lebedinsky <eyal at eyal dot emu dot id dot au>, gcc at gcc dot gnu dot org,Michael Elizabeth Chastain <mec dot gnu at mindspring dot com>
Date: Wed, 10 Dec 2003 07:27:44 -0500
Subject: Re: (printf) ("hello world\n");
References: <20031209204037.906D84B412@berman.michael-chastain.com> <jmvfopy2un.fsf@desire.geoffk.org> <3FD6DD9B.E35C742@eyal.emu.id.au> <jeiskpxal1.fsf@sykes.suse.de>

Andreas Schwab wrote:

Eyal Lebedinsky <eyal@eyal.emu.id.au> writes:

But without <stdio.h> the varargs attribute is not present
A varargs function is always a varargs function, whether it is prototyped
or not.  But without a proper prototype the behaviour is undefined.


Is it really true that the name printf is reserved? Is a C program not
allowed to define its own printf function (which might or might not be
varargs)? What's the story here?

Follow-Ups:
- Re: (printf) ("hello world\n");
  - From: Segher Boessenkool

References:
- (printf) ("hello world\n");
  - From: Michael Elizabeth Chastain
- Re: (printf) ("hello world\n");
  - From: Geoff Keating
- Re: (printf) ("hello world\n");
  - From: Eyal Lebedinsky
- Re: (printf) ("hello world\n");
  - From: Andreas Schwab

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