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Arrays and Alignment


I am declaring an array of an aligned type. However
it would appear that when used in an array, the alignment
is not maintained as I would expect. Here's a test-case.

#include <stdio.h>

typedef unsigned char achar __attribute__ ((__aligned__(32)));

achar a[2];

int main(int argc,char* argv[]){
   printf("__alignof__(achar):%u\n",__alignof__(achar));
   printf("__alignof__(a[1]):%u\n",__alignof__(a[1]));
   printf("&a: %8.8lX\n",(unsigned long)&a);
   printf("sizeof(a):%u\n",sizeof(a));
   printf("sizeof(a[0]):%u\n",sizeof(a[0]));
   printf("&a[0]: %8.8lX\n",(unsigned long)&a[0]);
   printf("&a[1]: %8.8lX\n",(unsigned long)&a[1]);
   return 0;
   }

% gcc -o main main.c ; main

__alignof__(achar):32
__alignof__(a[1]):1
&a: 08049740
sizeof(a):32
sizeof(a[0]):1
&a[0]: 08049740
&a[1]: 08049741         <<<<<<<<<<<< I expected this to be 08049760

% gcc --version
gcc (GCC) 3.2.2 20030222 (Red Hat Linux 3.2.2-5)

I expected the second element of the array to be aligned
as well as the first, since the alignment of the type is 32.

The Beatles were wrong: 1 & 1 & 1 is 1




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