Re: Problem with "<<" operator

[Pascal Francq <pfrancq at ulb dot ac dot be>]

On Fri, 25 Aug 2000, you wrote:
> On Aug 25, 2000, Joe Buck <jbuck@racerx.synopsys.com> wrote:
> 
> >> On Aug 25, 2000, Joe Buck <jbuck@racerx.synopsys.com> wrote:
> >> 
> >> > I believe that the C++ standard now requires an explicit & to indicate
> >> > a pointer-to-function
> >> 
> >> Nope, `&' is only required for pointer-to-members.  A function& decays
> >> to function* and, from that, I believe it decays to bool.
> 
> > A name of a function can be converted to a pointer to function.  But can
> > it be silently converted to a bool?
> 
> [conv.bool] allows pointers to be converted to bool.  It doesn't
> exclude pointers to functions.  Since function-to-pointer is an lvalue
> transformation, it can be followed by a boolean conversion.  Other
> implicit conversion sequences not involving a boolean conversion would
> be preferred, but that doesn't make the sequence invalid for purposes
> of overload resolution.  I think it's a bug in aCC.
> 
> -- 
> Alexandre Oliva   Enjoy Guarana', see http://www.ic.unicamp.br/~oliva/
> Red Hat GCC Developer                  aoliva@{cygnus.com, redhat.com}
> CS PhD student at IC-Unicamp        oliva@{lsd.ic.unicamp.br, gnu.org}
> Free Software Evangelist    *Please* write to mailing lists, not to me

But if you see the definition of the function "endl" in C++, you will see the
same of declaration (iostream.h) that my dummy function. And when you use
streams, you always write something like:

cout<<"Dummy"<<endl;

So why wuold it not work with another function?
 -- 


Ir. Pascal Francq
Researcher
Université Libre de Bruxelles
Faculty of Applied Mechanics
Avenue F.D. Roosevelt, 50
CP 165/41
B-1050 Brussels
BELGIUM
Tel. +32-2-650 47 65
Fax +32-2-650 27 10