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Re: c++ warning idea
On Sep 17, 1999, paulf@metaip.checkpoint.com wrote:
> Foo GiveAFoo();
> const Foo& rfoo = GiveAFoo();
> What happens is a temporary Foo object is returned, a reference to it
> stored, and the temporary object destructed, ending up with the equivalent
> of an uninitialized pointer.
> It is, in fact, pointless to initialize a reference to a temporary, but
> there are less than obvious ways where this can be accidentally done.
Nope, when a reference is bound to a temporary, the temporary will
remain at least until the reference itself goes out of scope.
[class.temporary]/5
--
Alexandre Oliva http://www.dcc.unicamp.br/~oliva IC-Unicamp, Bra[sz]il
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