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Re: c++/10694: [3.3/3.4 regression] Befriending a function in a classthat is only forward-declared


The following reply was made to PR c++/10694; it has been noted by GNATS.

From: Steven Bosscher <s.bosscher@student.tudelft.nl>
To: bangerth@dealii.org, gcc-gnats@gcc.gnu.org, gcc-bugs@gcc.gnu.org,
	nobody@gcc.gnu.org, gcc-prs@gcc.gnu.org
Cc:  
Subject: Re: c++/10694: [3.3/3.4 regression] Befriending a function in a class
 that is only forward-declared
Date: Sun, 11 May 2003 13:10:09 +0200

 http://gcc.gnu.org/cgi-bin/gnatsweb.pl?cmd=view%20audit-trail&database=gcc&pr=10694
 
 : Search converges between 2003-03-10-trunk (#149) and 2003-03-11-trunk 
 (#150).
 
 Line-numbered input is:
 ========================================
      1  template <class T> struct Y;
      2    
      3  template <class S> class X {
      4      template <class T> friend void Y<T>::member();
      5  };
      6    
      7  template <class T> struct Y {
      8      void member() {
      9        X<int>();
     10      }
     11  };
     12    
     13  template class Y<int>;
     14 
 
 ========================================
 
 
 Diagnostic output follows, from the last compiler tested:
 input: In instantiation of `X<int>':
 input:9:   instantiated from `void Y<T>::member() [with T = int]'
 input:13:   instantiated from here
 input:4: error: prototype for `template<class T> void Y::member()' does not
    match any in class `Y<T>'
 input:8: error: candidate is: void Y<T>::member()
 
 Compiler output follows, from the last compiler tested:
         .file   "input"
         .ident  "GCC: (GNU) 3.4 20030311 (experimental)"
 
 


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