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Re: c++/10146: [3.4 regression] [new parser] template function lookupfailure(s)


The following reply was made to PR c++/10146; it has been noted by GNATS.

From: Richard Guenther <rguenth at tat dot physik dot uni-tuebingen dot de>
To: Gabriel Dos Reis <gdr at integrable-solutions dot net>
Cc: Giovanni Bajo <giovannibajo at libero dot it>, <gcc-gnats at gcc dot gnu dot org>,
   <gcc-bugs at gcc dot gnu dot org>
Subject: Re: c++/10146: [3.4 regression] [new parser] template function lookup
 failure(s)
Date: Wed, 19 Mar 2003 13:32:12 +0100 (CET)

 On 19 Mar 2003, Gabriel Dos Reis wrote:
 
 > Richard Guenther <rguenth at tat dot physik dot uni-tuebingen dot de> writes:
 >
 > | On Wed, 19 Mar 2003, Giovanni Bajo wrote:
 > |
 > | >
 > | > http://gcc.gnu.org/cgi-bin/gnatsweb.pl?cmd=view%20audit-trail&database=gcc&p
 > | > r=10146
 > | >
 > | > To sum it up:
 > | >
 > | > >Foo<int>().template foo<U>(u); // does not work
 > | > >Foo<int>().template bar<U>(u); // does not work
 > | >
 > | > These should compile.
 > | >
 > | > >Foo<int>().foo(u);             // does work ??
 > | > >Foo<int>::foo(u);              // does work ??
 > | > >Foo<int>().bar(u);             // does work ??
 > | >
 > | > Yes, because the template parameter of the template member function is
 > | > deduced from the call. What's wrong with them?
 > |
 > | I think foo() and bar() needs to be qualified with the template keyword
 > | due to two-stage namelookup. But I may be wrong (dont have a standard
 > | to look at).
 >
 > Two-phase name lookup has nothing to do here.  The Foo<int> part is
 > -not- dependent, therefore there need not be any extra "template"
 > qualifier.
 
 Ah, ok - only for Foo<T>:: it would be dependent, yes? So gcc should
 reject or at least warn about the extra "template" here? (gcc3.2 bails
 out with a parse error for Foo<int>::template foo(u);)
 
 Richard.
 
 --
 Richard Guenther <richard dot guenther at uni-tuebingen dot de>
 WWW: http://www.tat.physik.uni-tuebingen.de/~rguenth/
 


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