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Re: c++/10146: [3.4 regression] [new parser] template function lookup failure(s)
- From: "Giovanni Bajo" <giovannibajo at libero dot it>
- To: nobody at gcc dot gnu dot org
- Cc: gcc-prs at gcc dot gnu dot org,
- Date: 19 Mar 2003 12:26:01 -0000
- Subject: Re: c++/10146: [3.4 regression] [new parser] template function lookup failure(s)
- Reply-to: "Giovanni Bajo" <giovannibajo at libero dot it>
The following reply was made to PR c++/10146; it has been noted by GNATS.
From: "Giovanni Bajo" <giovannibajo at libero dot it>
To: <gcc-gnats at gcc dot gnu dot org>,
<rguenth at tat dot physik dot uni-tuebingen dot de>,
<gcc-bugs at gcc dot gnu dot org>,
<nobody at gcc dot gnu dot org>,
<gcc-prs at gcc dot gnu dot org>
Cc:
Subject: Re: c++/10146: [3.4 regression] [new parser] template function lookup failure(s)
Date: Wed, 19 Mar 2003 13:18:09 +0100
http://gcc.gnu.org/cgi-bin/gnatsweb.pl?cmd=view%20audit-trail&database=gcc&p
r=10146
To sum it up:
>Foo<int>().template foo<U>(u); // does not work
>Foo<int>().template bar<U>(u); // does not work
These should compile.
>Foo<int>().foo(u); // does work ??
>Foo<int>::foo(u); // does work ??
>Foo<int>().bar(u); // does work ??
Yes, because the template parameter of the template member function is
deduced from the call. What's wrong with them?
Note: I did not verify since I cannot compile GCC 3.4.
Giovanni Bajo