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Re: c++/10146: [3.4 regression] [new parser] template function lookup failure(s)


The following reply was made to PR c++/10146; it has been noted by GNATS.

From: "Giovanni Bajo" <giovannibajo at libero dot it>
To: <gcc-gnats at gcc dot gnu dot org>,
	<rguenth at tat dot physik dot uni-tuebingen dot de>,
	<gcc-bugs at gcc dot gnu dot org>,
	<nobody at gcc dot gnu dot org>,
	<gcc-prs at gcc dot gnu dot org>
Cc:  
Subject: Re: c++/10146: [3.4 regression] [new parser] template function lookup failure(s)
Date: Wed, 19 Mar 2003 13:18:09 +0100

 http://gcc.gnu.org/cgi-bin/gnatsweb.pl?cmd=view%20audit-trail&database=gcc&p
 r=10146
 
 To sum it up:
 
 >Foo<int>().template foo<U>(u); // does not work
 >Foo<int>().template bar<U>(u); // does not work
 
 These should compile.
 
 >Foo<int>().foo(u);             // does work ??
 >Foo<int>::foo(u);              // does work ??
 >Foo<int>().bar(u);             // does work ??
 
 Yes, because the template parameter of the template member function is
 deduced from the call. What's wrong with them?
 
 Note: I did not verify since I cannot compile GCC 3.4.
 
 Giovanni Bajo
 


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