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Re: c++/9460: parse error on template member function
- From: "Giovanni Bajo" <giovannibajo at libero dot it>
- To: nobody at gcc dot gnu dot org
- Cc: gcc-prs at gcc dot gnu dot org,
- Date: 29 Jan 2003 09:16:00 -0000
- Subject: Re: c++/9460: parse error on template member function
- Reply-to: "Giovanni Bajo" <giovannibajo at libero dot it>
The following reply was made to PR c++/9460; it has been noted by GNATS.
From: "Giovanni Bajo" <giovannibajo@libero.it>
To: "Wolfgang Bangerth" <bangerth@ticam.utexas.edu>,
"Oliver Schoenborn" <oliver.schoenborn@utoronto.ca>
Cc: <gcc-gnats@gcc.gnu.org>,
<gcc-bugs@gcc.gnu.org>
Subject: Re: c++/9460: parse error on template member function
Date: Wed, 29 Jan 2003 10:09:39 +0100
----- Original Message -----
From: "Wolfgang Bangerth" <bangerth@ticam.utexas.edu>
To: "Oliver Schoenborn" <oliver.schoenborn@utoronto.ca>
Cc: <gcc-gnats@gcc.gnu.org>
Sent: Tuesday, January 28, 2003 10:14 PM
Subject: Re: c++/9460: parse error on template member function
> It would be different if you would call
> Foo().F1<A> ();
> in which case you would have to use
> Foo().template F1<A> ();
Sorry for the confusion. The problem is, the compiler still has symmetric
behaviour:
Foo().F1<A>() compiles with no errors, while it needs the template keyword.
(accept-illegal)
In my first code snippet, if you remove Bar::F1, the code fails to compile.
(reject-legal).
Giovanni Bajo