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Re: c++/8330: GCC 3.2 cannot deduce typename in derived template class.
- From: lerdsuwa at gcc dot gnu dot org
- To: brobanx at msn dot com, gcc-bugs at gcc dot gnu dot org, gcc-prs at gcc dot gnu dot org, nobody at gcc dot gnu dot org
- Date: 24 Oct 2002 13:58:28 -0000
- Subject: Re: c++/8330: GCC 3.2 cannot deduce typename in derived template class.
- Reply-to: lerdsuwa at gcc dot gnu dot org, brobanx at msn dot com, gcc-bugs at gcc dot gnu dot org, gcc-prs at gcc dot gnu dot org, nobody at gcc dot gnu dot org, gcc-gnats at gcc dot gnu dot org
Synopsis: GCC 3.2 cannot deduce typename in derived template class.
State-Changed-From-To: open->closed
State-Changed-By: lerdsuwa
State-Changed-When: Thu Oct 24 06:58:26 2002
State-Changed-Why:
Not a bug. If the type you want to access is in base class
that depends on template parameter ("Base<C>" depends on "C"
in this case), you need to qualify the type with base class name, i.e. "typename base_class<T>::base_type".
"typename base_type" is not a valid C++ syntax there.
http://gcc.gnu.org/cgi-bin/gnatsweb.pl?cmd=view%20audit-trail&database=gcc&pr=8330