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Re: [PATCH][RFC][match.pd] optimize (X & C) == N when C is power of 2


On Mon, Jul 27, 2015 at 09:11:12AM +0100, Kyrill Tkachov wrote:
> On 25/07/15 03:19, Segher Boessenkool wrote:
> >On Fri, Jul 24, 2015 at 09:09:39AM +0100, Kyrill Tkachov wrote:
> >>This transformation folds (X % C) == N into
> >>X & ((1 << (size - 1)) | (C - 1))) == N
> >>for constants C and N where N is positive and C is a power of 2.
> >For N = 0 you can transform it to
> >
> >	((unsigned)X % C) == N
> >
> >and for 0 < N < C you can transform it to
> >
> >	X > 0 && ((unsigned)X % C) == N          (or X >= 0)
> >
> >and for -C < N < 0 it is
> >
> >	X < 0 && ((unsigned)X % C) == N + C      (or X <= 0)
> >
> >and for other N it is
> >
> >	0.
> >
> >For N not a constant, well, do you really care?  :-)
> >
> >(That second case might eventually fold to your original expression).
> 
> Yeah, these avoid the potentially expensive mask,

Fun fact: the current code ends up using the exact same mask, for some
targets.

> but introduce more operations,
> which I believe may not be desirable at this stage.

It is getting rid of the (expensive) division/modulo.  In many cases it
could get rid of the sign test, or hoist it to some outer structure, hard
to test here though (at least, I have no idea how to do that).

> Unless these transformations are ok for match.pd I'll try to implement this 
> transformation
> at RTL expansion time.

If you have to do conditional jumps, the RTL optimisers will not be able
to do very much :-(


Segher


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