Re: [DOC] clearer description of -std= (try 2)

["Manuel López-Ibáñez" <lopezibanez at gmail dot com>]

On 18/01/2008, Ralf Wildenhues <Ralf.Wildenhues@gmx.de> wrote:
> Hello Manuel,
>
> In your patch you mention that gnu89 is the default now but gnu99 will
> become the default eventually.  Will -ansi then switch to mean c99?

I only rewrite what was written. I really can't speculate.

> If this has been decided already, might as well present it that way,
> or at least give the reader hope that it might happen.  So I suggest
> adding a sentence up front:
>
>   Switch from the GNU dialect used to its base standard.  In C mode, this
>   is equivalent to @samp{-std=c89}. In C++ mode, it is equivalent to
>   @samp{-std=c++98}.
>

I think "switch to" is likely to cause confusion. (Does this mean that
-std=gnu14 -ansi is equivalent to -std=c14? I know the answer is no
but...) I think what you want to mean is "Use the default base
standard". But I prefer my current wording.

Thanks,

Manuel.