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Re: [C++] enumerators and check_initializer


Mark Mitchell <mark@codesourcery.com> writes:

| Gabriel Dos Reis wrote:
| > Hi,
| > 
| >   We have the following code in decl.c:check_initializer():
| > 
| > 
| >   if (TREE_CODE (decl) == CONST_DECL)
| >     {
| >       gcc_assert (TREE_CODE (decl) != REFERENCE_TYPE);
| > 
| >       DECL_INITIAL (decl) = init;
| > 
| >       gcc_assert (init != NULL_TREE);
| >       init = NULL_TREE;
| >     }
| > 
| > 
| > If decl is a CONST_DECL, then obviously the assert
| > 
| >       gcc_assert (TREE_CODE (decl) != REFERENCE_TYPE);
| > 
| > is trivially true.  Is it a typo for
| > 
| >       gcc_assert (TREE_CODE (TREE_TYPE (decl)) != REFERENCE_TYPE);
| > 
| > where one wanted to check that the decl is not a reference type?
| 
| Yes.

Fixed with this.  Thanks!

-- Gaby
2006-01-15  Gabriel Dos Reis  <gdr@integrable-solutions.net>
 
 	* decl.c (check_initializer): Fix thinko.
 
*** decl.c	(revision 109730)
--- decl.c	(local)
*************** check_initializer (tree decl, tree init,
*** 4578,4584 ****
  
    if (TREE_CODE (decl) == CONST_DECL)
      {
!       gcc_assert (TREE_CODE (decl) != REFERENCE_TYPE);
  
        DECL_INITIAL (decl) = init;
  
--- 4578,4584 ----
  
    if (TREE_CODE (decl) == CONST_DECL)
      {
!       gcc_assert (TREE_CODE (type) != REFERENCE_TYPE);
  
        DECL_INITIAL (decl) = init;
  


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