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Re: Further C front end tests
Andreas Schwab wrote:-
> See 188.8.131.52p3 and footnote 83:
> Similarly, if the operand is the result of a  operator, neither the &
> operator nor the unary * that is implied by the  is evaluated and the
> result is as if the & operator were removed and the  operator were
> changed to a + operator.
> 83) Thus, &*E is equivalent to E (even if E is a null pointer), and
> &(E1[E2]) to ((E1)+(E2)).
> So it all boils down to "arithmetic on void *", but _not_ "dereferencing
> void *".
This seems to be referring to evaluation. Constraints on used operators