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Re: fix opt/8634
On Tue, 8 Apr 2003, Geoff Keating wrote:
> If you take a linear operation (that is, O(n)), and then you perform
> it K*n times for some fixed constant K, then the program is O(n*n),
> which is quadratic.
Sorry, but this is certainly not how big-O notation is supposed to work:
O(K·n) = O(n) for any fixed K > 0, by definition.
Gerald
--
Gerald "Jerry" pfeifer at dbai dot tuwien dot ac dot at http://www.pfeifer.com/gerald/