Re: GCC ignores function attributes

[Nikos Chantziaras <realnc at gmail dot com>]

On 12/06/14 03:31, Jonathan Wakely wrote:
> On 11 June 2014 23:36, Nikos Chantziaras wrote:
> > According to the documentation:
> >
> > https://gcc.gnu.org/onlinedocs/gcc-4.8.2/gcc/Function-Attributes.html#Function-Attributes
> >
> > and more specific, the example about the visibility attribute:
> >
> >    void __attribute__ ((visibility ("protected")))
> >    f () { /* Do something. */; }
> >
> > doesn't work for me. I have this C++ function prototype:
> >
> >    const SDL_AudioSpec& __attribute__((visibility("default")))
> >    spec();
> >
> > Compiling this with g++ 4.8.2 gives me:
> >
> >    warning: 'visibility' attribute ignored on non-class types
>
> I think the attribute binds to the return type here, which is a
> reference (not a class type) so can't be given visibility.
>
> This applies the attribute to the function, not the return type:
>
> const SDL_AudioSpec& spec() __attribute__((visibility("hidden")));

I've found that this also works:

__attribute__((visibility("hidden"))) const SDL_AudioSpec& spec();

The only one that doesn't, is the documented one :-/  Documentation bug?