Re: Extending GNU C extensions

["Michael Gong" <mwgong at cs dot utoronto dot ca>]

We used gentle compiler construction system to build an AspectC compiler ( 
www.aspectc.net ), which is a source-to-source translation tool and 
introduce the concept of Aspect-Oriented Programming ( AOP ) methodology to 
C.

But if you only add small sugars to C, in my opinion, using gentle system 
might be overkill.

Hope this helps.


----- Original Message ----- 
From: "Amit Choudhary" <amit2030@yahoo.com>
To: <gcc-help@gcc.gnu.org>
Sent: Monday, September 25, 2006 1:44 PM
Subject: Re: Extending GNU C extensions


> In my opinion, you can use macros for some of the things, and
> then write a program in perl to pre-process the code, before
> invoking gcc, to convert the rest of the new constructs to GNU C
> constructs. But there may be other options.
>
> Hope this helps.
>
> Regards,
> Amit
>
> --- Alpt <alpt@freaknet.org> wrote:
>
> > Hi there,
> >
> > I'd like to extend the syntax of GNU C with few basic
> > constructs.
> > Their main purpose is to simplify the use of repetitive
> > statements and to add
> > some syntax sugar (but not to much).
> > All the new constructs can be converted to normal GNU C.
> >
> > The idea is to use a translator that converts the new syntax
> > to the GNU C one,
> > in this way, it can be compatible to gcc.
> >
> > What is the best way to achieve this?
> > Using flex&bison, M4, the sources of gcc, perl regexp, a
> > specific tool?
> >
> > What I'm looking for is a simple way to translate this new
> > simple syntax to
> > GNU C, without rewriting a compiler.
> >
> >
> > These are some of the new syntax constructs:
> >
> > -  Struct
> >
> > element<-struct = value;   ==> struct->element = value;
> >
> > element<`struct = value;   ==> struct.element = value;
> > struct`>element = value;   ==> struct.element = value;
> >
> > - High Level Boolean Logic
> >
> > A &|| B       ==>    (A && B) || (A || B)
> > In english it's the same of: A and/or B
> >
> > (A && |B, C, D, E|)     ==>   (A && B) || (A && C) || (A && D)
> > || (A && E)
> > (A || |B, C, D, E|)     ==>   (A || B) || (A || C) || (A || D)
> > || (A || E)
> >   ==>  A || B || C || D || E
> >
> > (A || &B, C, D, E&)     ==>   (A || B) && (A || C) && (A || D)
>
>
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