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Re: temporary auto_ptr
On 9/29/05, John Love-Jensen wrote:
> The f2 function returns an auto_ptr<const A>.
> You are trying to return an auto_ptr<const B>.
> An auto_ptr<const B> is not an auto_ptr<const A>, regardless if a "B is an
> A".
And it does not matter that there is an implicit conversion possible
between auto_ptr<const B>& and auto_ptr<const A> ?
(unless I explicitly state I want to do it, as in "f1" )
Regards,
Dima.