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Re: Template friends
- From: Al Niessner <Al dot Niessner at jpl dot nasa dot gov>
- To: list gcc <gcc-help at gcc dot gnu dot org>
- Date: Wed, 09 Feb 2005 10:10:31 -0800
- Subject: Re: Template friends
- References: <1107971713.26422.9.camel@morte.jpl.nasa.gov>
In the previous post I mistakenly referenced my declaration as looking
like h<>() in 14.5.3.2 when I should have said preempt<>() in 14.5.3.1's
example. I can also change the friend the statement to be 'friend int
foobar<T>(A<T> &);' and it fails with the same error.
On Wed, 2005-02-09 at 09:55 -0800, Al Niessner wrote:
> I figure my parser is wrong and g++ is correct, but I have no idea as to
> why.
>
> g++ --version == 3.4.1
>
> Code fragment:
>
> template<class T> class A;
> template<class T> int foobar(const A<T> &x);
>
> template<class T> class A
> {
> ...
> friend int foobar<>(const A<T> &);
> ...
> }
>
> gives me this:
> error: `dim' is neither function nor member function; cannot be declared
> friend
>
> So, I opened my copy of ISO 14882;2003 and read 14.5.3 and cannot find
> what is wrong with my syntax. In fact, it looks similar to h<>() in the
> 14.5.3.2 example. So, what is wrong with the above syntax?
>
--
Al Niessner
818.354.0859
All opinions stated above are mine and do not necessarily reflect those
of JPL or NASA.
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