Re: Equivalent to gcc -M to build a list of *objects*

[Matthieu Moy <Matthieu dot Moy at imag dot fr>]

Nick Patavalis <npat@inaccessnetworks.com> writes:

> Runnning gcc -M on a ".c" file, gives you a list of all header files
> it includes, directly or indirectly. What other kind of dependency
> would you like to detect? This whole description is very fuzzy.

If you know Ada, I want the equivalent of gnatmake. 

In the following schema :

file2.h   file1.h  file3.h
   |    \  |          |
   |     \ |          |
file2.c  file1.c   file3.c
         main()

If we  follow the  convention that any  function declared in  XXX.h is
implemented  in XXX.c,  then it  is  easy to  deduce that  to build  a
project for  wich the main  function is in  file1.c, then, we  have to
compile  file1.c and file2.c.  The list  of object  files to  build is
"file1.o  file2.o". Therefore,  the rule  is  easy to  generate for  a
Makefile.

In this example, gcc -M file1.c | sed s/.[ch]\>/.o/ will give the right
list.

But in the following case, it doesn't :

file3.h  file2.h file1.h
   |   \   |   \  |       
   |    \  |    \ |       
file3.c file2.c  file1.c   
                 main()

because file1.c doesn't include either directly or indirectly file3.h,
but file2.c will contain references to symbols defined in file3.o.

-- 
Matthieu