Flushing output before \n

[Michel Ducharme <ducharme at saturne dot uqah dot uquebec dot ca>]

Hello,

I am having trouble in flushing a line of text before a new
line character (\n) is output.

For example, I have :

   cout << "Reading file...";
   ReadFile();
   cout << "\b\b\b - " << n << " records.\n";

The text from the first "cout" is not output until the second
"cout" is executed, because the first "cout" does not terminate
the line with a new line (\n) character.

I would like the first "cout" to be output when executed so
that is would be visible while the "ReadFile()" operation is
taking place.

I have tried using "system ("stty raw -echo")" before the first
"cout" and "system ("stty -raw echo")" after the last one, as
well as some other parameters of the "stty" command, but none
of these did achieve the desired result; the output of the first
"cout" instruction is still only seen after the new line character
is output by the second "cout".

Has anyone encountered this problem and has found a solution?

Sincerely,

Michel Ducharme.
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